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[tcp] Add code comment why we have to copy the ByteBuffer
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1 changed files with 7 additions and 2 deletions
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@ -1030,12 +1030,15 @@ public class XmppTcpTransportModule extends ModularXmppClientToServerConnectionM
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}
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}
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}
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}
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@SuppressWarnings("ReferenceEquality")
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@Override
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@Override
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public ByteBuffer input(ByteBuffer inputData) throws SSLException {
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public ByteBuffer input(ByteBuffer inputData) throws SSLException {
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ByteBuffer accumulatedData;
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ByteBuffer accumulatedData;
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if (pendingInputData == null) {
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if (pendingInputData == null) {
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accumulatedData = inputData;
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accumulatedData = inputData;
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} else {
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} else {
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assert pendingInputData != inputData;
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int accumulatedDataBytes = pendingInputData.remaining() + inputData.remaining();
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int accumulatedDataBytes = pendingInputData.remaining() + inputData.remaining();
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accumulatedData = ByteBuffer.allocate(accumulatedDataBytes);
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accumulatedData = ByteBuffer.allocate(accumulatedDataBytes);
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accumulatedData.put(pendingInputData)
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accumulatedData.put(pendingInputData)
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@ -1116,9 +1119,11 @@ public class XmppTcpTransportModule extends ModularXmppClientToServerConnectionM
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}
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}
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private void addAsPendingInputData(ByteBuffer byteBuffer) {
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private void addAsPendingInputData(ByteBuffer byteBuffer) {
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// TODO: Why doeesn't simply
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// Note that we can not simply write
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// pendingInputData = byteBuffer;
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// pendingInputData = byteBuffer;
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// work?
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// we have to copy the provided byte buffer, because it is possible that this byteBuffer is re-used by some
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// higher layer. That is, here 'byteBuffer' is typically 'incomingBuffer', which is a direct buffer only
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// allocated once per connection for performance reasons and hence re-used for read() calls.
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pendingInputData = ByteBuffer.allocate(byteBuffer.remaining());
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pendingInputData = ByteBuffer.allocate(byteBuffer.remaining());
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pendingInputData.put(byteBuffer).flip();
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pendingInputData.put(byteBuffer).flip();
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