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Fix OpenPgpV4Fingerprint.getKeyId()

This commit is contained in:
Paul Schaub 2018-08-17 17:28:17 +02:00
parent ea6f89e2bc
commit fe52a7f398
Signed by: vanitasvitae
GPG key ID: 62BEE9264BF17311

View file

@ -16,10 +16,8 @@
package org.pgpainless.key;
import javax.annotation.Nonnull;
import java.math.BigInteger;
import java.nio.ByteBuffer;
import java.nio.charset.Charset;
import java.util.Arrays;
import org.bouncycastle.openpgp.PGPPublicKey;
import org.bouncycastle.openpgp.PGPPublicKeyRing;
@ -89,17 +87,11 @@ public class OpenPgpV4Fingerprint implements CharSequence, Comparable<OpenPgpV4F
* @return key id
*/
public long getKeyId() {
byte[] bytes = Hex.decode(toString().getBytes(Charset.forName("UTF-8")));
ByteBuffer buf = ByteBuffer.wrap(bytes);
buf.position(12);
return buf.getLong();
byte[] bytes = new BigInteger(toString(), 16).toByteArray();
if (bytes.length != toString().length() / 2) {
bytes = Arrays.copyOfRange(bytes, 1, bytes.length);
}
byte[] lower8Bytes = Arrays.copyOfRange(bytes, 12, 20);
ByteBuffer byteBuffer = ByteBuffer.allocate(8);
byteBuffer.put(lower8Bytes);
byteBuffer.flip();
return byteBuffer.getLong();
}
@Override